(C+4)(c^2-3c+5)=

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Solution for (C+4)(c^2-3c+5)= equation:


Simplifying
(C + 4)(c2 + -3c + 5) = 0

Reorder the terms:
(4 + C)(c2 + -3c + 5) = 0

Reorder the terms:
(4 + C)(5 + -3c + c2) = 0

Multiply (4 + C) * (5 + -3c + c2)
(4(5 + -3c + c2) + C(5 + -3c + c2)) = 0
((5 * 4 + -3c * 4 + c2 * 4) + C(5 + -3c + c2)) = 0
((20 + -12c + 4c2) + C(5 + -3c + c2)) = 0
(20 + -12c + 4c2 + (5 * C + -3c * C + c2 * C)) = 0
(20 + -12c + 4c2 + (5C + -3cC + c2C)) = 0

Reorder the terms:
(20 + 5C + -12c + -3cC + 4c2 + c2C) = 0
(20 + 5C + -12c + -3cC + 4c2 + c2C) = 0

Solving
20 + 5C + -12c + -3cC + 4c2 + c2C = 0

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + 5C + -12c + -3cC + 4c2 + -20 + c2C = 0 + -20

Reorder the terms:
20 + -20 + 5C + -12c + -3cC + 4c2 + c2C = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 5C + -12c + -3cC + 4c2 + c2C = 0 + -20
5C + -12c + -3cC + 4c2 + c2C = 0 + -20

Combine like terms: 0 + -20 = -20
5C + -12c + -3cC + 4c2 + c2C = -20

Add '12c' to each side of the equation.
5C + -12c + -3cC + 4c2 + 12c + c2C = -20 + 12c

Reorder the terms:
5C + -12c + 12c + -3cC + 4c2 + c2C = -20 + 12c

Combine like terms: -12c + 12c = 0
5C + 0 + -3cC + 4c2 + c2C = -20 + 12c
5C + -3cC + 4c2 + c2C = -20 + 12c

Add '-4c2' to each side of the equation.
5C + -3cC + 4c2 + -4c2 + c2C = -20 + 12c + -4c2

Combine like terms: 4c2 + -4c2 = 0
5C + -3cC + 0 + c2C = -20 + 12c + -4c2
5C + -3cC + c2C = -20 + 12c + -4c2

Reorder the terms:
20 + 5C + -12c + -3cC + 4c2 + c2C = -20 + 12c + -4c2 + 20 + -12c + 4c2

Reorder the terms:
20 + 5C + -12c + -3cC + 4c2 + c2C = -20 + 20 + 12c + -12c + -4c2 + 4c2

Combine like terms: -20 + 20 = 0
20 + 5C + -12c + -3cC + 4c2 + c2C = 0 + 12c + -12c + -4c2 + 4c2
20 + 5C + -12c + -3cC + 4c2 + c2C = 12c + -12c + -4c2 + 4c2

Combine like terms: 12c + -12c = 0
20 + 5C + -12c + -3cC + 4c2 + c2C = 0 + -4c2 + 4c2
20 + 5C + -12c + -3cC + 4c2 + c2C = -4c2 + 4c2

Combine like terms: -4c2 + 4c2 = 0
20 + 5C + -12c + -3cC + 4c2 + c2C = 0

The solution to this equation could not be determined.

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